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Home » 8x + 20y &= 40 \quad \text(from (2))\times 4 - Midis

8x + 20y &= 40 \quad \text(from (2))\times 4 - Midis

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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📌 Una pelota rebota hasta alcanzar el 75% de su altura anterior cada vez que toca el suelo. Si se deja caer desde una altura de 128 metros, ¿hasta qué altura rebotará en el cuarto golpe?

📌 En el primer rebote: 128 × 0.75 = 96 m. Segundo: 96 × 0.75 = 72 m. Tercero: 72 × 0.75 = 54 m. Cuarto: 54 × 0.75 = 40.5 m.

📌 Si el interés compuesto sobre $1500 a una tasa anual del 10% es de $331, ¿cuántos años se han pasado?

📌 La fórmula para el interés compuesto es A = P(1 + r)^t. Aquí, A = 1500 + 331 = 1831, P = 1500, r = 0.10. Entonces, 1831 = 1500(1.1)^t. Dividiendo: 1.21 = (1.1)^t. Tomando log: log(1.21) = t × log(1.1). Por lo tanto, t = log(1.21)/log(1.1) ≈ 2.

📌 En un triángulo rectángulo, la hipotenusa es de 25 cm y un cateto mide 15 cm. ¿Cuál es la longitud del otro cateto?

📌 Usando el teorema de Pitágoras: a² + b² = c². Sea un cateto 15 cm, hipotenusa 25 cm. Entonces 15² + b² = 25² → 225 + b² = 625 → b² = 400 → b = 20 cm.

📌 Un cono circular recto tiene un radio de base de 6 cm y una altura inclinada de 10 cm. ¿Cuál es su volumen?

📌 Primero, hallamos la altura usando Pitágoras: h² + 6² = 10² → h² = 100 - 36 = 64 → h = 8 cm. Volumen = (1/3)πr²h = (1/3)π(36)(8) = 96π cm³ ≈ 301.44 cm³. Sin embargo, dado que se requiere valor exacto: (1/3)π(36)(8) = 96π.

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