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Home » Altitude to 9: $\frac1089 = 12$ - Midis

Altitude to 9: $\frac1089 = 12$ - Midis

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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6x^3 = 108 \Rightarrow x^3 = 18 \Rightarrow x = \sqrt[3]{18}
x \approx 2.62 \quad \text{but exact form: } x = \sqrt[3]{18}
However, note \( 18 = 2 \cdot 3^2 \), so no perfect cube — but problem...
Check: \( 2.62^3 \approx 18 \)? Yes.
But since \( 6x^3 = 108 \Rightarrow x^3 = 18 \Rightarrow x = \sqrt[3]{...
So the width is \( \sqrt[3]{18} \) meters.
But wait — factor:
\( 6x^3 = 108 \Rightarrow x^3 = 18 \Rightarrow x = \sqrt[3]{18} \)
Alternatively, check if integer solution: try \( x = 3 \):
\( 6(27) = 162 > 108 \)

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