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Cancel: \(x + 2\). - Midis

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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📌 2r + 2 = (3 - \sqrt{5})r - 3 + \sqrt{5}

📌 2r - (3 - \sqrt{5})r + 5 - \sqrt{5} = 0

📌 r = rac{\sqrt{5} - 5}{-1 + \sqrt{5}} = rac{-(5 - \sqrt{5})}{\sqrt{5} - 1}

📌 Multiply numerator and denominator by \(\sqrt{5} + 1\):

📌 r = -rac{(5 - \sqrt{5})(\sqrt{5} + 1)}{(\sqrt{5} - 1)(\sqrt{5} + 1)} = -rac{5\sqrt{5} + 5 - 5 - \sqrt{5}}{5 - 1} = -rac{4\sqrt{5}}{4} = -\sqrt{5}.

📌 Thus, \( r = \sqrt{5} \) or \( r = -\sqrt{5} \). These correspond to pairs \((x, y)\) such that \(x = \pm \sqrt{5} y\), with \(y

📌 e 0\), and \(x

📌 e y\) (to avoid division by zero in the original expression).

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