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Home » Solving for \(s\), we divide both sides by \(\sqrt2\): - Midis

Solving for \(s\), we divide both sides by \(\sqrt2\): - Midis

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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Radius of base at half height = 10 cm / 2 = 5 cm
Volume of smaller pyramid = (1/3) × (5 cm)^2 × 7.5 cm = 62.5 cubic cm
#### 62.5**Question 1:
A quadratic equation is given as \(ax^2 + bx + c = 0\). If \(a = 2\),...
The quadratic formula is \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4 \cdot 2 \cdot (-6)}}{2 \cdot 2}
Simplify inside the square root:
x = \frac{4 \pm \sqrt{16 + 48}}{4}
x = \frac{4 \pm \sqrt{64}}{4}
x = \frac{4 \pm 8}{4}

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\[ \cos^2(\theta) = 1 - \frac{9}{25} = \frac{16}{25} \]
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