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sweet 16 party ideas - Midis

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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📌 registers = 10 × 20 = 200 bytes

📌 Improved system: 16 registers × 2 bytes = 32 bytes

📌 But question asks how many total bytes does the ENIAC register memory occupy — answer = 200

📌 But this diverges.

📌 Alternate interpretation from history: ENIAC had 20-digit precision per accumulator, 10 accumulators, 4 bits per digit → 20 × 4 = 80 bits = 10 bytes per register → 200 bytes

📌 Improved system: 16 registers × 2 bytes = 32 bytes — but ENIAC is 200

📌 But the question likely intends:

📌 ENIAC: 20 digits × 10 registers × (4 bits / 8 bits per byte) × 1 byte per 4 bits = 20 × 10 = 200 bytes

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