We are given that $ \fracdVdt = k \sin \theta $, and $ \theta = 60^\circ $, so $ \sin \theta = \frac{\sqrt3}2 $. Substituting:

We are given that $ \fracdVdt = k \sin \theta $, and $ \theta = 60^\circ $, so $ \sin \theta = \frac{\sqrt3}2 $. Substituting: - Midis

📅 March 12, 2026 👤 scraface

Mar 12, 2026

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