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Home » We want $ 64 \times (1.125)^n-1 > 95 $ - Midis

We want $ 64 \times (1.125)^n-1 > 95 $ - Midis

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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Sustituyendo los valores conocidos:
6^2 = 20 + 2xy \implies 36 = 20 + 2xy \implies 2xy = 16 \implies xy =...
Ahora sustituimos de nuevo en la identidad de la suma de cubos:
x^3 + y^3 = (x + y)(x^2 - xy + y^2) = 6(20 - 8) = 6 \times 12 = 72
Por lo tanto, el valor de $x^3 + y^3$ es $\boxed{72}$.
Pregunta: Si $a + b = 10$ y $a^2 + b^2 = 58$, encuentra $a^3 + b^3$.
Usamos la identidad para la suma de cubos:
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
Sabemos $a + b = 10$ y $a^2 + b^2 = 58$. Para encontrar $ab$, usamos:
10^2 = 58 + 2ab \implies 100 = 58 + 2ab \implies 2ab = 42 \implies ab...

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