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Home » Shay Cormac’s Latest Move? The Secrets Behind His Revolutionary Idea Exposed! - Midis

Shay Cormac’s Latest Move? The Secrets Behind His Revolutionary Idea Exposed! - Midis

📅 March 12, 2026 👤 scraface

Mar 12, 2026

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📌 eq b $ implies $ heta

📌 eq \phi $, so $ S $ is purely imaginary. However, the original question may expect a real value. Re-examining:

📌 Let $ S = rac{(a + b)^2 + (a - b)^2}{a^2 - b^2} = rac{2a^2 + 2b^2}{a^2 - b^2} $. Let $ a = 1 $, $ b = i $:

📌 S = rac{2(1 + (-1))}{1 - (-1)} = 0, ext{ but } a^2 - b^2 = 1 - (-1) = 2, ext{ numerator } 2(1 + (-1)) = 0 \Rightarrow S = 0.

📌 Another example: $ a = 1 $, $ b = e^{i2\pi/3} $:

📌 a^2 = 1, b^2 = e^{i4\pi/3}, a^2 - b^2 = 1 - e^{i4\pi/3}, a^2 + b^2 = 1 + e^{i4\pi/3}.

📌 Numerator: $ 2(1 + e^{i4\pi/3}) $, denominator: $ 1 - e^{i4\pi/3} $, so $ S = 2 \cdot rac{1 + e^{i4\pi/3}}{1 - e^{i4\pi/3}} $. Multiply numerator and denominator by $ e^{-i2\pi/3} $:

📌 S = 2i \cdot rac{e^{i2\pi/3} + e^{i2\pi/3}}{e^{i2\pi/3} - e^{-i2\pi/3}} = ext{complicated}.

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#### 4014.41
A computational neuroscience engineer trains a brain-computer interfac...
This is exponential growth: $ a_n = 64 \times (1.125)^{n-1} $
We want $ 64 \times (1.125)^{n-1} > 95 $
Divide both sides: $ (1.125)^{n-1} > 95 / 64 = 1.484375 $
$ (n-1) \log(1.125) > \log(1.484375) $
$ \log(1.125) \approx 0.051161 $
$ \log(1.484375) \approx 0.17116 $
So $ n - 1 > 0.17116 / 0.051161 \approx 3.348 $
Thus $ n > 4.348 $ → smallest integer $ n = 5 $

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